The two electrons of 1S state are attracted to the 10e+ nucleus strongly, so they are much closer to the nucleus than the 2S electron.

Neon ion (Ne7+) has two electrons in 1S orbital, and one electron in 2S orbital.

To confirm the third electron of neon enters the orbit of two (not one) de Broglie's wavelength, we try computing the energy of the three-electron neon ion (Ne7+). So it can be said that also in the neon ion (Ne8+), the orbital planes of the two electrons are almost perpendicular to each other. ( This little difference is thought to be caused by Ne8+ big positive charges attracting some negative charges around it. The ionization energy of Ne8+ is very big, so the error is only 0.19%. So when the total energy of Ne8+ is -2563.0 eV, the number of de Broglie's waves contained in one orbits becomes just 1.00000.Īs I said above, the experimental value of the Ne8+ energy is -2558.03 eV. Results of r1 and WN in which last VY is zero in Ne8+. ( When the last VY is zero, the electrons move on the stable orbits. Table 2 shows the results of r1 and WN (= number of de Broglie's waves contained in one quarter of the orbit ) in which last VY ( y component of electron 1's velocity after moving one quarter of its orbit ) is zero at various energy levels of Ne8+. In the upper program, input the Neon atomic number Z = 10 after running it. JAVA program to compute two-electron atoms. (In this program, we use the new units, 1 MM = 10 -14 meter, 1 SS = 10 -23 second, 1 MM/SS = 10 9 m/s. Here we use the following sample programs. See the Top page (He) or Li+ page about the detailed computing methods. We suppose the two electrons of Ne8+ are orbiting like Fig. So the experimental value of the total (ground state) energy is -2558.03 eV ) The sum of the ionization energies of neon ion ( Ne8+ ) is 1195.83 + 1362.20= 2558.03 eV This means that also in neon, only two '1S' electrons are much closer to the nucleus than other electrons. Ionization energies of the neon atom (eV).Īs shown in this Table 1, the ionization energies of 1S electrons ( red values) are much bigger than other ionization energies. Here we show the ionization energies of neon.

(Fig.1) Two-electron Atomic Model ( He, Li+, Be2+, B3+, C4+. Then, we can apply this new atomic structure to other two-electron atoms (ions) ? Estimated eight valence electrons in Neon atom (Ne).Surprisingly, this new atomic structure of the Bohr's helium can be applied to other two-electron atoms (ions ), Lithium ion (Li+), Beryllium (Be2+), Boron (B3+) and Carbon (C4+) ions, too.įurthermore, the ionization (ground state) energy of the three-electron atom lithium (Li) can be calculated correctly using the approximate '2S' Bohr orbit. This model can explain the phenomena of Pauli exclusion principle correctly, because there is no space for the third electron to enter this new two-electron Bohr atom. In this new successful Bohr model, the two electrons of the helium atom (He) are moving on the orbits of just one de Broglie's wavelength which are perpendicular to each other. Our new Bohr model has succeeded in calculating the Helium ionization energy more correctly than the quantum mechanical variational methods as shown in the Top page. Top page (correct Bohr model including the two-electron atoms). Bohr's Neon atomic structure New Bohr model Neon (Ne)